0.4v^2+2.5=2v

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Solution for 0.4v^2+2.5=2v equation: 



0.4v^2+2.5=2v

We move all terms to the left:

0.4v^2+2.5-(2v)=0

a = 0.4; b = -2; c = +2.5;
Δ = b2-4ac
Δ = -22-4·0.4·2.5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{2}{0.8}=2+0.4/0.8$

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